7.3 (C++)
请参照map添加两个模版函数map2 。
EXAMPLE OUTPUT
135
501
867
1123
1456
1789
主程序 (不能修改)
#include <string>
#include <vector>
#include <iostream>
using namespace std;
template <typename A, typename R>
vector<R> map(const vector<A> & x, R (*map_func)(const A &)) {
vector<R> res;
for (int i = 0; i < x.size(); ++ i)
res.push_back(map_func(x[i]));
return res;
}
#include "source.cpp"
#include <sstream>
// using namespace std;
int to_int(const string & text) {
stringstream ss(text);
int val;
ss >> val;
return val;
}
vector<string> split(const string & line,
const string & delimiter=" ") {
vector<string> words;
int st = 0;
while (st < line.size()) {
int end = line.find(delimiter, st);
if (end == st) st += delimiter.size();
else {
if (end == -1) {
words.push_back(line.substr(st));
break;
}
words.push_back(line.substr(st, end-st));
st = end + delimiter.size();
}
}
return words;
}
template <typename E>
void print_vector(const vector<E> & c) {
for (int i = 0; i < c.size(); ++ i) {
cout << c[i] << endl;
}
}
int add(const int & x, const int & y) {
return x + y;
}
int main() {
string line1 = "123 456 789";
string line2 = "12 45 78";
vector<string> words = split(line1);
vector<int> data1 = map(words, to_int);
words = split(line2);
vector<int> data2 = map(words, to_int);
vector<int> sum1 = map2(data1, data2, add);
print_vector(sum1);
vector<int> sum2 = map2(data1, 1000, add);
print_vector(sum2);
}
我的答案
template <typename A, typename R>
vector<R> map2(const vector<A> & x,const vector<A> & y, R (*map_func)(const A &,const A &)) {
vector<R> res;
for (int i = 0; i < x.size(); ++ i)
res.push_back(map_func(x[i],y[i]));
return res;
}
template <typename A, typename R>
vector<R> map2(const vector<A> & x,const int & y, R (*map_func)(const A &,const A &)) {
vector<R> res;
for (int i = 0; i < x.size(); ++ i)
res.push_back(map_func(x[i],y));
return res;
}