io.2

Please write a C function that can read a data in three different formats.

EXAMPLE INPUT

2018年12月30日
12/3/2018
2018-12-15
Dec. 5, 2018
EXAMPLE OUTPUT
2018年12月30日
12/3/2018
2018/12/15
Wrong format

主程序 (不能修改)

#include <stdio.h>
#include <stdlib.h>

enum Format { CHINESE, MONTH_FIRST, YEAR_FIRST, WRONG };

struct Date
{
    int year;
    int month;
    int day;
    enum Format format;
};

void printDate(struct Date date) {
    switch (date.format) {
    case CHINESE: printf("%d年%d月%d日\n", date.year, date.month, date.day); break;
    case MONTH_FIRST: printf("%d/%d/%d\n", date.month, date.day, date.year); break;
    case YEAR_FIRST: printf("%d/%d/%d\n", date.year, date.month, date.day); break;
    default: puts("Wrong format");
    }
}

#include "source.c"

int main() {
    for (int i = 0; i < 4; ++ i) {
        struct Date date = readDate();
        printDate(date);
    }
}

我的答案

struct Date readDate(){
    struct Date date;
    char s[100];
    fgets(s,1000,stdin);
    if(sscanf(s,"%d年%d月%d日", &date.year, &date.month, &date.day)==3){
        date.format=CHINESE;
    }
    else if(sscanf(s,"%d/%d/%d", &date.month, &date.day, &date.year)==3){
        date.format=MONTH_FIRST;
    }
    else if(sscanf(s,"%d-%d-%d", &date.year, &date.month, &date.day)==3){
        date.format=YEAR_FIRST;
    }
    else{
        date.format=WRONG;
    }
    return date;
}