struct.2

Sort student records by last name in a reverse order.

主程序 (不能修改)

struct T_student {
    double student_id;
    char last_name[9];
    char first_name[8];
    double age;
    char sex[2];
    double major;
    double advisor;
    char city_code[4];
};

struct T_student student[] = {
    { 1001,    "Smith",   "Linda", 18, "F", 600, 1121, "BAL" },
    { 1002,      "Kim",   "Tracy", 19, "F", 600, 7712, "HKG" },
    { 1003,    "Jones",  "Shiela", 21, "F", 600, 7792, "WAS" },
    { 1004,    "Kumar",  "Dinesh", 20, "M", 600, 8423, "CHI" },
    { 1005,  "Gompers",    "Paul", 26, "M", 600, 1121, "YYZ" },
    { 1006,  "Schultz",    "Andy", 18, "M", 600, 1148, "BAL" },
    { 1007,     "Apap",    "Lisa", 18, "F", 600, 8918, "PIT" },
    { 1008,   "Nelson",   "Jandy", 20, "F", 600, 9172, "BAL" },
    { 1009,      "Tai",    "Eric", 19, "M", 600, 2192, "YYZ" },
    { 1010,      "Lee",   "Derek", 17, "M", 600, 2192, "HOU" },
    { 1011,    "Adams",   "David", 22, "M", 600, 1148, "PHL" },
    { 1012,    "Davis",  "Steven", 20, "M", 600, 7723, "PIT" },
    { 1014,   "Norris", "Charles", 18, "M", 600, 8741, "DAL" },
    { 1015,      "Lee",   "Susan", 16, "F", 600, 8721, "HKG" },
    { 1016, "Schwartz",    "Mark", 17, "M", 600, 2192, "DET" },
    { 1017,   "Wilson",   "Bruce", 27, "M", 600, 1148, "LON" },
    { 1018, "Leighton", "Michael", 20, "M", 600, 1121, "PIT" },
    { 1019,     "Pang",  "Arthur", 18, "M", 600, 2192, "WAS" },
    { 1020, "Thornton",     "Ian", 22, "M", 520, 7271, "NYC" },
    { 1021,  "Andreou",  "George", 19, "M", 520, 8722, "NYC" },
    { 1022,    "Woods", "Michael", 17, "M", 540, 8722, "PHL" },
    { 1023,  "Shieber",   "David", 20, "M", 520, 8722, "NYC" },
    { 1024,   "Prater",   "Stacy", 18, "F", 540, 7271, "BAL" },
    { 1025,  "Goldman",    "Mark", 18, "M", 520, 7134, "PIT" },
    { 1026,     "Pang",    "Eric", 19, "M", 520, 7134, "HKG" },
    { 1027,    "Brody",    "Paul", 18, "M", 520, 8723, "LOS" },
    { 1028,     "Rugh",    "Eric", 20, "M", 550, 2311, "ROC" },
    { 1029,      "Han",     "Jun", 17, "M", 100, 2311, "PEK" },
    { 1030,    "Cheng",    "Lisa", 21, "F", 550, 2311, "SFO" },
    { 1031,    "Smith",   "Sarah", 20, "F", 550, 8772, "PHL" },
    { 1032,    "Brown",    "Eric", 20, "M", 550, 8772, "ATL" },
    { 1033,    "Simms", "William", 18, "M", 550, 8772, "NAR" },
    { 1034,      "Epp",    "Eric", 18, "M",  50, 5718, "BOS" },
    { 1035,  "Schmidt",   "Sarah", 26, "F",  50, 5718, "WAS" }
};

#define len(t) (sizeof t / sizeof(struct T_##t))

#include "source.c"
#include <stdio.h>

    
void print_a_record(struct T_student * s) {
    printf("%d\t%s\t%s\t%d\t%s\t%d\t%d\t%s\n", 
            (int)s->student_id,
            s->last_name,
            s->first_name,
            (int)s->age,
            s->sex,
            (int)s->major,
            (int)s->advisor,
            s->city_code);
}

void print_all_records() {
    for (int i = 0; i < len(student); ++ i) {
        print_a_record(student + i);
    }
}

int main() {
    sort_by_last_name(); // Just do it
    print_all_records();
}

我的答案

#include <stdio.h>
#include <string.h>
void sort_by_last_name(){
    for(int i=0;i<33;i++)
    {
        for(int j=0;j<33;j++)
        {
            if(strcmp(student[j].last_name,student[j+1].last_name)<0)
            {
               struct T_student temp;
               temp=student[j];
               student[j]=student[j+1];
               student[j+1]=temp;
                }
        }
    }    
}